Answer:
68m/s
Explanation:
Given parameters:
Mass = 30g = 0.03kg
Potential energy = 70J
Unknown:
Velocity = ?
Solution;
Since there is no loss in energy, the potential energy and kinetic energy will be the same when shot;
P.E = K.E
K.E = P.E = [tex]\frac{1}{2}[/tex] m v²
70 = [tex]\frac{1}{2}[/tex] x 0.03 x v²
70 = 0.015v²
v = 68m/s