A scientist heated a tank containing 50 g of water. The specific heat of water is 4.18 The temperature of the water increased from 25 to 37°C. How much heat energy did the water absorb?

Respuesta :

Answer:

b

Explanation:

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Answer:

Find the solution's specific heat on a chart or use the specific heat of water, which is 4.186 joules per gram Celsius. Substitute the solution's mass (m), temperature change (delta T) and specific heat (c) into the equation Q = c x m x delta T, where Q is the heat absorbed by the solution.

Explanation:

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