Question

Assume the clock for a 4-bit binary counter is 80 kHz. The output frequency of the fourth stage (Q3) is

Answer 1

Answer:

5kHz

Explanation:

There are four stages so N = 2⁴ = 16.

The frequency at nth stage is given by

$f_n = \frac{f_{clk}}{N} = \frac{80kHz}{16} = 5kHz$