Question

A magnetic field (B=3.2x10^-3 T) passes perpendicular through a circular loop of wire ( radius= 5.0 cm) what is the magnetic flux through the hoop?

Answer 1

Answer:

25.12 x 10^-6 T/m^2

Explanation:

Magnetic flux is

fi = B * A * cos theta

as filed passes perepndicular theta is 90degrees and cos theta is 1

B=3.2x10^-3 T

A = pi * r ^2

A = 3.14 * (0,05m )^2

A = 0,00785

A = 7,85 m 10^-3 m2

fi = 3.2x10^-3 T * 7,85 m 10^-3 m2

fi = 25.12 x 10^-6 T/m^2