Question

how many moles of HF are needed to react with 0.300 mol of Na2SiO3?

Answer 1

Na2SiO3(s) + 8 HF(aq) ___> H2SiF6(aq) + 2 NaF(aq) + 3 H2O(l)
as per the equation , one mole of Na2SiO3 requires 8 moles of HF.
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Answer 2

The moles of HF are needed to react with 0.300 mol of Na₂SiO₃ is 2.4 moles.

What is stoichiometry of the reaction?

Stoichiometry of any reaction tells about the amount of species present before and after the completion of chemical reaction.

Given chemical reaction will be represent as:

Na₂SiO₃(s) + 8HF(aq) → H₂SiF₆(aq) + 2NaF(aq) + 3H₂O(l)

From the stoichiometry of the reaction it is clear that:

1 mole of Na₂SiO₃ = react with 8 moles of HF

0.30 mole of Na₂SiO₃ = react with 8×0.30=2.4 moles of HF

Hence, required moles of HF is 2.4 moles.

To know more about stoichiometry, visit the below link:

https://brainly.com/question/16060199