Answer:
Question 675528: A ball is thrown vertically upward with an initial velocity of 48 feet per second. If the ball started its flight at a height of 8 feet, then its height s at time t can be determined by s(t)=-16t^2+48t+8 where s(t) is measured in feet above the ground and t is the number of seconds of flight.
Step-by-step explanation: