Respuesta :
Answer:
0.00005
Step-by-step explanation:
We have the average fraction defective as p = 1%
= 0.01
N = 100
Then 95.5% deviation = 2σ
From there we have,
σ = √p*(1-p)/n
When we input these values, into the formula, we will have
σ = √0.01(1-0.01)/100
= √0.01(0.99)/100
= √0.000099
= 0.00995
The LCL = p - 2σ
= 0.01 - 0.00995
= 0.00005
lower control chart limit be is 0.00005
The 95.5% lower control chart limit be is 0.0005.
Given,
The average fraction percent in the past defective as p = 1% = 0.01
Sample size N = 400
Then ,
According to the question ,
95.5% deviation = 2x
We have,
x = [tex]\frac{\sqrt{p (1-p)} }{n}[/tex]
We put these values, into the formula,
x = [tex]\frac{\sqrt{0.01 ( 1 - 0.01) } }{400}[/tex]
= [tex]= \frac{\sqrt{(0.01) (0.99)} }{400}[/tex]
= [tex]\frac{0.99}{400}[/tex]
= 0.0000245
The LCL = p - 2x
= 0.01 - 0.0000245
= 0.00005
The Lower control chart limit be is 0.00005
For the more information about Standard deviation click the link given below.
https://brainly.com/question/23907081