Question

A 0.56 kg model rocket produces 53 newtons of upward thrust as it shoots upward off the launch pad. With what acceleration meters per second-squared does the rocket launch?

Answer 1

resultant force = thrust – weight

acceleration = resultant force (newtons, N) divided by mass (kilograms, kg).

Acceleration = resultant force divided by mass

53N/0.56

=94.64 approximately 95

= 95m/s^2

This means that, every second, the speed of the rocket increases by 95m/s2

the S.I unit of Acceleration is meter per second square.

Answer 2

The acceleration in meters per second squared that the rocket launch is 94.64m/s²

According to Newton's second law, the formula for calculating the force acting on a body is expressed as;

F = ma

F is the applied force

m is the mass of the rocket

a is the acceleration of the rocket

Given the following parameters

Mass = 0.56kg

Force = 53N

Substitute the given parameters into the formula as shown:

F = ma

a = F/m

a = 53/0.56

a = 94.64m/s²

Hence the acceleration in meters per second-squared that the rocket launch is 94.64m/s²

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