Respuesta :

Answer:

Wavelength in water, [tex]\lambda=1.12\times 10^6\ m[/tex]

Explanation:

Given that,

A submarine uses sub-radio communication at 200 Hz.

The index of refraction, n = 1.333

The refractive index of a medium is given by :

[tex]\mu=\dfrac{c}{v}\\\\\mu=\dfrac{c}{\lambda_m f}\\\\\lambda_m=\dfrac{c}{\mu f}\\\\\lambda_m=\dfrac{3\times 10^8}{1.333\times 200}\\\\=1.12\times 10^6\ m[/tex]

So, the wavelength of the electromagnetic waves in water is [tex]1.12\times 10^6\ m[/tex].

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