Respuesta :

Answer:

0.9612 g

Explanation:

First we calculate how many moles are there in 3.00 g of CCl₃F, using its molar mass:

  • 3.00 g CCl₃F ÷ 137.37 g/mol = 0.0218 mol CCl₃F

Now, we need to calculate how many grams of N₂O would have that same number of molecules, or in other words, the same amount of moles.

Thus we calculate how many grams would 0.0218 moles of N₂O weigh, using the molar mass of N₂O :

  • 0.0218 mol N₂O * 44.013 g/mol = 0.9612 g N₂O

The  mass of dinitrogen monoxide is 0.9612 g

  • The calculation is as follows:

The number of  moles are there in 3.00 g of CCl₃F, using its molar mass:

= 3.00 g CCl₃F ÷ 137.37 g/mol

= 0.0218 mol CCl₃F

Now the mass should be

=[ 0.0218 mol N₂O ×  44.013 g/mol

= 0.9612 g N₂O

Learn more: https://brainly.com/question/5763151?referrer=searchResults

ACCESS MORE
EDU ACCESS
Universidad de Mexico