The length of a rectangle is 3 centimeters less than five times its width. Its area is 14 square centimeters. Find the dimensions of the rectangle. W= L=​

Respuesta :

Step-by-step explanation:

Let breadth =x

Length=5x-3

As we know that in a rectangle

[tex]\boxed{\sf Area=lb}[/tex]

  • Substitute the values

[tex]{:}\hookrightarrow\sf x (5x-3)=14 [/tex]

[tex]{:}\hookrightarrow\sf 5x^2-3x=14[/tex]

[tex]{:}\hookrightarrow\sf 5x^2-3x-14=0 [/tex]

[tex]{:}\hookrightarrow\sf 5x^2-10x+7x-14=0 [/tex]

[tex]{:}\hookrightarrow\sf 5x (x-2)+7 (x-2)=0[/tex]

[tex]{:}\hookrightarrow\sf (x-2)(5x+7)=0 [/tex]

[tex]{:}\hookrightarrow\sf x-2=0\quad or\quad 5x+7=0 [/tex]

[tex]{:}\hookrightarrow\sf x=2\:or\:x=\dfrac {-7}{5}[/tex]

  • Ignore negative value

[tex]{:}\hookrightarrow\sf Breadth =2cm[/tex]

[tex]{:}\hookrightarrow\sf Length=5 (2)-3=10-3=7cm[/tex]

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