Answer:
(A). x ≥ [tex]\frac{16}{5}[/tex] and x ≤ - [tex]\frac{3}{4}[/tex]
Step-by-step explanation:
5x - 4 ≥ 12 ⇔ 5x ≥ 16 ⇒ x ≥ [tex]\frac{16}{5}[/tex]
and
12x + 5 ≤ - 4 ⇔ 12x ≤ - 9 ⇔ 4x ≤ - 3 ⇒ x ≤ - [tex]\frac{3}{4}[/tex]
