Answer:
[tex]D.\ 30.39\ in^2[/tex]
Step-by-step explanation:
[tex]In\ order\ to\ find\ the\ area\ of\ the\ whole\ figure,\ we\ need\ to\ find\ the\ areas\ of\ the\ individual\\polygons\ respectively.[/tex][tex]Hence,\\First,\\Lets\ find\ the\ area\ of\ the\ rectangle.\\We\ are\ given,\\Length=6.9\\Breadth=3.1\\Hence,\\Area=Length*Breadth\\[/tex]
[tex]Area\ of\ the\ rectangle=21.39\ in^2\\Now, \\Lets\ find\ the\ area\ of\ the\ square.\\Length\ of\ one\ side\ of\ the\ square=3\ in.\\Hence, Area\ of\ the\ square=n^2=3^2=9\ in^2\\[/tex]
[tex]Hence,\\Total\ Area\ of\ the\ Figure= Area\ of\ Rectangle+Area\ of\ the\ Square\\Hence,\\Total\ Area\ of\ the\ Figure=21.39+9\\=30.39\ in^2[/tex]
