Respuesta :
-4(3r - 2) - 2(r + 1) = 0
-12r + 8 - 2r - 2 = 0
-14r + 6 = 0
-14r = - 6
r = 6/14
r = 3/7
Answer:
[tex]\huge\boxed{\sf -14r+6}[/tex]
Step-by-step explanation:
[tex]\sf -4(3r-2)-2(r+1)\\\\Resolving \ Parenthesis\\\\= -12r+8-2r-2\\\\Combining \ like \ terms\\\\= -12r -2r +8-2\\\\= -14r+6\\\\\rule[225]{225}{2}[/tex]
Hope this helped!