Answer:
The effective dose is [tex]E = 11.1\ mS_v[/tex]
Explanation:
From the question we are told that
The whole-body does received from 100-keV neutrons is [tex]D_1 = 0.30 mGy = 0.30 *10^{-3} \ Gy[/tex]
The whole-body does received from 1.5-MeV neutrons is [tex]D_2 = 0.19 mGy = 0.19 *10^{-3} \ Gy[/tex]
The whole-body does received from gamma rays is [tex]D_3= 4.3 mGy = 4.3 *10^{-3} \ Gy[/tex]
Generally from the table of radiation weight factor ,
The radiation weight factor for 100-keV neutrons is [tex]R_1 = 10[/tex]
The radiation weight factor for 100-keV neutrons is [tex]R_2 = 20[/tex]
The radiation weight factor for gamma rays is [tex]R_3 = 1[/tex]
Generally the effective does is mathematically represented as
[tex]E = R_1 * D_1 + R_2 * D_2 + R_3 * D_3[/tex]
=> [tex]E = 10 * 0.30 +20 * 0.19 +1 * 4.3[/tex]
=> [tex]E = 11.1\ mS_v[/tex]
