A family that owns two automobiles is selected at random. Suppose that the probability that the older car is American is 0.80, the probability that the newer car is American is 0.70, and the probability that both the older and the newer cars are American is 0.60.

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Answer:

Probability [New car is also American] = 0.75

Explanation:

Given:

P(Older) = 0.80

P(New) = 0.70

P(Older and New) = 0.60

Find:

Probability [New car is also American]

Computation:

P(Older and New) = P(Older)[P(New given Old)]

P(New given Old) = 0.60  / 0.80

P(New given Old) = 0.75

Probability [New car is also American] = 0.75

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