Question

Maurice has a paper bag with three hard candies: two blueberries and one green apple. Yvonne and Kate ask if they can each have one. Yvonne closes her eyes and picks a candy from the bag, hoping for a blueberry. What are the chances she will pick a blueberry candy?

Answer 1

Answer:

The chances of Yvonne to get a blue berry candy in the two cases are 1 and 1/2 in case 1 and 2/3 in the case 2.

Step-by-step explanation:

Maurice has a paper bag  with three hard candies

2 blueberries and 1 green apple

Yvonne and Kate want 1 candy each

It is not mentioned that ether Kate has taken a candy already before Yvonne or not so we will consider both the cases

Case 1

If Kate has picked a candy before Yvonne

• If Kate gets an Apple green candy then the probability or Yvonne to get a Blueberry  will be = 2/2 = 1 ( as there will 2 blueberry candy left in the bag)
• If Kate has taken a Blueberry candy then there will be 1 blueberry and 1 apple green candy in the bag so the probability of Yvonne to get a Blueberry candy will be  = 1/2

Case 2

If Kate has not taken any candy from the bag before Yvonne

Probability that Yvonne will get a blueberry candy will be = 2/3

Therefore the chances of Yvonne to get a blue berry candy in the two cases are 1 and 1/2 in case 1 and 2/3 in the case 2.