Complete Question
A certain refrigerator, operating between temperatures of -8.00°C and +23.2°C, can be approximated as a Carnot refrigerator.
What is the refrigerator's coefficient of performance? COP
(b) What If? What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a heat pump? COP
Answer:
a
[tex]COP = 8.49[/tex]
b
[tex]COP_1 = 9.49[/tex]
Explanation:
From the question we are told that
The lower operation temperature of refrigerator is [tex]T_1 = -8.00^oC = 265 \ K[/tex]
The upper operation temperature of the refrigerator is [tex]T_2 = 23.2 ^oC = 296.2 \ K[/tex]
Generally the refrigerators coefficient of performance is mathematically represented as
[tex]COP = \frac{T_1}{T_2 - T_1 }[/tex]
=> [tex]COP = \frac{265}{296.2 - 265 }[/tex]
=> [tex]COP = 8.49[/tex]
Generally if a refrigerator (operating between the same temperatures) was instead used as a heat pump , the coefficient of performance is mathematically represented as
[tex]COP_1 = \frac{T_2}{ T_2 - T_1}[/tex]
=> [tex]COP_1 = \frac{296.2}{ 296.2 - 265 }[/tex]
=> [tex]COP_1 = 9.49[/tex]
The coefficient of performance if the refrigerator is used as a heat pump is 9.5.
The given parameters;
The coefficient of performance if the refrigerator is used as a heat pump is calculated as follows;
[tex]COP = \frac{T_2}{T_2 - T_1}\\\\COP = \frac{296.2}{296.2 - 265} \\\\COP =9.5[/tex]
Thus, the coefficient of performance if the refrigerator is used as a heat pump is 9.5.
"Your question is not complete, it seems to be missing the following information";
A certain refrigerator, operating between temperatures of -8.00°C and +23.2°C, can be approximated as a Carnot refrigerator.
What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a heat pump?
Learn more about coefficient of performance here: https://brainly.com/question/20713684
