Answer:
[tex]y=10(3.16)^x[/tex]
Step-by-step explanation:
Given equation is,
log(y) = 0.5x + 1
We can rewrite this equation as,
[tex]\text{log}_{10}(y)=0.5x+1[/tex]
y = [tex]10^{(0.5x+1)}[/tex]
[If [tex]\text{log}_a(b)=c[/tex], then [tex]b = a^{c}[/tex]]
y = [tex]10(10)^{0.5x}[/tex]
y = [tex]10[(10)^{0.5}]^x[/tex]
y = [tex]10(3.16)^x[/tex] [Since, [tex]10^{0.5}=3.16[/tex]]
Therefore, [tex]y=10(3.16)^x[/tex] will be the answer.
