for each line state the slope, for a bonus state the slope l l & ⟂ to the slope of the given line
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Answer:
Slope of line = [tex]\frac{1}{2}[/tex]
Slope of parallel line = [tex]\frac{1}{2}[/tex]
Slope of perpendicular line = (-2)
Step-by-step explanation:
Slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is,
[tex]m_1=\frac{y_2-y_1}{x_2-x_1}[/tex]
Therefore, equation of a line passing through points (1, -3) and (-1, -4) will be,
[tex]m_1=\frac{-4-(-3)}{-1-1}[/tex]
[tex]=\frac{1}{2}[/tex]
If the slope of a line parallel to the given line is [tex]m_{2}[/tex],
Then by the property of parallel lines,
[tex]m_1=m_2[/tex]
Therefore, slope of the parallel line will be [tex]\frac{1}{2}[/tex].
Property of perpendicular lines,
[tex]m_1\times m_2=-1[/tex]
[tex]\frac{1}{2}\times m_2=-1[/tex]
[tex]m_2=-2[/tex]
Therefore, slope of the perpendicular line will be (-2).