Find the equation of the line
passing through the points (3,1)
and (7,-7).
y = [? ]x + []

Given:
A line passes through two points are (3,1) and (7,-7).
To find:
The equation of the line.
Solution:
The line passes through two points are (3,1) and (7,-7). So, the equation of line is
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-1=\dfrac{-7-1}{7-3}(x-3)[/tex]
[tex]y-1=\dfrac{-8}{4}(x-3)[/tex]
[tex]y-1=-2(x-3)[/tex]
Using distributive property, we get
[tex]y-1=-2(x)-2(-3)[/tex]
[tex]y-1=-2x+6[/tex]
Adding 1 on both sides, we get
[tex]y=-2x+6+1[/tex]
[tex]y=-2x+7[/tex]
Therefore, the equation of line is [tex]y=-2x+7[/tex]. So, the missing values are -2 and 7 respectively.