Respuesta :

Given:

A line passes through two points are (3,1) and (7,-7).

To find:

The equation of the line.

Solution:

The line passes through two points are (3,1) and (7,-7). So, the equation of line is

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

[tex]y-1=\dfrac{-7-1}{7-3}(x-3)[/tex]

[tex]y-1=\dfrac{-8}{4}(x-3)[/tex]

[tex]y-1=-2(x-3)[/tex]

Using distributive property, we get

[tex]y-1=-2(x)-2(-3)[/tex]

[tex]y-1=-2x+6[/tex]

Adding 1 on both sides, we get

[tex]y=-2x+6+1[/tex]

[tex]y=-2x+7[/tex]

Therefore, the equation of line is [tex]y=-2x+7[/tex]. So, the missing values are -2 and 7 respectively.

ACCESS MORE