Question

What is the mass in grams of 0.338 mol of glucose (C6H12O6)? step by step

Answer 1

The amount in mole of a substance = mass in gram * (1 mole of the substance/ molar mass of the substance).
molar mass of C6H12O6 = (12*6) + (1*12) + (16*6) = 180.
Let the mass of glucose in gram = G
0.338 = G X (I/180)
0.338 = G/180 
G = 0.338 X 180 = 60.84g.

Answer 2

The mass in grams of 0.338 mole of glucose, C₆H₁₂O₆ is 60.84 g

The mole of a substance is related to it's mass and molar mass by the following equation:

Mole = mass / molar mass

• With the above formula, we can obtain the mass of 0.338 mole of glucose, C₆H₁₂O₆. this can be obtained as follow:

Mole of C₆H₁₂O₆ = 0.338 mole

Molar mass of C₆H₁₂O₆ = (12×6) + (1×12) + (16×6) = 180 g/mol

Mass of C₆H₁₂O₆ =?

Mass = mole × molar mass

Mass of C₆H₁₂O₆ = 0.338 × 180

Mass of C₆H₁₂O₆ = 60.84 g

Therefore, the mass of 0.338 mole of glucose, C₆H₁₂O₆ is 60.84 g

Learn more: https://brainly.com/question/18834543