Question

There are 14 performers who will present their acts this weekend at a comedy club. One of the performers insists on being the last stand-up comic of the evening, and another performer wants to be the first. Determine how many different ways can the appearances be scheduled.

Answer 1

Given:
14 performers
first spot claimed ; last spot claimed.

14 - 1 - 1 = 12

12 spots remaining for everybody else. Permutation.

12!  = 479,001,600