Respuesta :
Answer:
C)-212.5
i see this on a quiz on iready
Step-by-step explanation:
Rate of a quantity is always in comparison to some other quantity's change. Susan’s average change in elevation, in meters per hour is given by: Option C) -212.5 meters/ hour.
How to find the average rate of change of something?
Let the thing that is changing be y and the thing with which the rate is being compared is x, then we have the average rate of change of y as x changes as:
[tex]\text{Average rate} = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]
where when
[tex]x = x_1, y = y_1\\and \\x = x_2, y = y_2[/tex]
(its final value - initial value for both dependent and independent variable).
The average change in elevation in meters per hour is ratio of change in elevation in meters to time taken to do it in hours.
Therefore, it is calculated as:
[tex]A = \dfrac{ 680 - 1530}{4} = \dfrac{-850}{4} = -212.5 \: \rm meters/hour[/tex]
(if t was initial time, and t+4 was final time, then t+4-t = 4)
(also, initial height was 1530
Thus, Susan’s average change in elevation, in meters per hour is given by: Option C) -212.5 meters/ hour
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