Question

¡¡first convert revolutions per second to
radians per second by multiplying by
2pi (2). The angular acceleration is
radius*(ang. Velocity)2
.After you find acceleration, force(tension)is just mass∗
accel. >>
An athlete whirls an 8.45 kg hammer tied
to the end of a 1.4 m chain in a simple horizontal circle where you should ignore any vertical
deviations. The hammer moves at the rate of
0.595 rev/s.
What is the centripetal acceleration of the
hammer? Assume his arm length is included
in the length given for the chain.
Answer in units of m/s

004 (part 2 of 2)
What is the tension in the chain?
Answer in units of N

Answer 1

Answer:

a. 5.23 m/s² b. 44.23 N

Explanation:

a. What is the centripetal acceleration of the  hammer?  

The centripetal acceleration a = rω² where r = radius of circle and ω = angular speed.

Now r = length of chain = 1.4 m and ω = 0.595 rev/s = 0.595 × 2π/s = 3.74 rad/s.

So a = rω²

= 1.4 m × (3.74 rad/s)²

= 5.23 m/s²

b. What is the tension in the chain?

The tension in the chain, T = ma where m = mass of hammer = 8.45 kg and a = centripetal acceleration of hammer = 5.23 m/s². This tension is the centripetal force on the hammer.

So, T = 8.45 kg × 5.23 m/s²

= 44.23 N