Question

In the diagram above, mZABC = (3x-1), mZCBD = (2x)°, and mZDBE = (4x + 1)º. Find mZABC, mZCBD, and
mZDBE. Assume that ZABE is a straight angle.
A. ZABC = 290, mZCBD = 20°, and mZDBE = 1319
B. ZABC = 59°, mZCBD = 20°, and mZDBE = 101°
C. m ABC = 59, mZCBD = 40°, and MZDBE = 81°
Dm ABC = 61º, mZCBD = 390, and mDBE = 80°

Answer 1

Step-by-step explanation:

3x -1 +2x + 4 x +1 = 180

9x = 180

X= 20

<ABC = 59

< CB D = 40

< DBE = 81