Given:
The ratio of the length to the width of a rectangle is 10:6.
Perimeter = 160 meters
To find:
The measure of the width.
Solution:
Let the length and width of the rectangle be 10x and 6x respectively.
Perimeter of a rectangle is
[tex]P=2(l+w)[/tex]
where, l is length and w is width.
Putting P=160, l=10x and w=6x, we get
[tex]160=2(10x+6x)[/tex]
[tex]160=2(16x)[/tex]
[tex]160=32x[/tex]
Divide both sides by 32.
[tex]\dfrac{160}{32}=x[/tex]
[tex]5=x[/tex]
Now,
[tex]Width=6x[/tex]
[tex]Width=6(5)[/tex]
[tex]Width=30[/tex]
Therefore, the width of the rectangle is 30 meters.