Respuesta :

Answer:

1.2*10^-2

Step-by-step explanation:

-3^0 is 1, because anything to the power of 0 (except for 0) is always equal to 1. 1 is an integer, so this is not the answer.

18/3=6, and 6 is an integer, so this is not the answer either.

1.2*10^-2 = 1.2*0.01 = 0.012, which is not an integer, so this is the answer.

49 is an integer, so this is not the answer:

Therefore, the answer to this problem is 1.2*10^-2

Hope this helped!

Answer:

[tex]1.2*(10-2)[/tex] cannot be written as an integer.

Explanation:

Fractions and decimals are not integers. All whole numbers and natural numbers are integers.

You can immediately identify that [tex]1.2*(10-2)[/tex]  cannot be written as an integer because the decimal is 1.2 and the only way it could become an integer is if it was multiplied by a number ending in 5 or with 5 as a factor (5,1 0, 15, 20, and so on). Also, it has a decimal point that isn't being multiplied by another decimal/fraction. In some cases, decimals or fractions multiplied by each other can equal an integer, but it's that's not the case in this instance.

However, if you couldn't identify this or you needed to check you answer, you could solve the expressions:

[tex]1.2*(10-2)\\1.2*(8)\\9.6[/tex]

9.6 is a decimal, therefore it is not an integer.

[tex]-3 + 0 = -3\\-3*0= 0[/tex]

I don't know if you were attempting to add or multiply, but in both cases, the sum and product equal an integer.

[tex]\frac{18}{3} = 6[/tex]

18 is divisible by 3, so you can assume that the quotient will be an integer. (3*6 = 18, to check your answer)

(To know if something is divisible by three, add the numbers of the dividend. If they equal a number that can be divided by three, you can assume that you'll get an integer and whole number.

For example: 1 + 8 = 9, 3*3 = 9)

[tex]\sqrt{49} =7[/tex]

The square root of 49 is 7. If you've memorized your square roots, you could identify quickly that the square root would be an integer. If you haven't it's okay, keep working on it!

I hope this helps!