Which statement accurately describes the vector shown?
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Answer:
magnitude of √61 and a direction angle equal to approximately 40°
Step-by-step explanation:
I inserted the x,y axis into a vector calculator to get the magnitude and angle :D
The magnitude of the vector is √61 and the direction of the angle is 40 degrees option (C) magnitude of √61 and a direction angle equal to approximately 40° is correct.
It is defined as the quantity that has magnitude as well as direction also the vector always follows the sum triangle law.
We have a vector shown in the picture.
The coordinate of the vector are:
The tail coordinate = (0, 0)
The head coordinate = (6, 5)
We can find the magnitude of the vector using the distance formula:
The distance formula can be given as:
[tex]\rm M=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]\rm M=\sqrt{(6-0)^2+(5-0)^2}[/tex]
M = √61
The direction of the angle:
tanA = 5/6
tanA = 0.8333
A =39.80 ≈ 40 degrees
Thus, the magnitude of the vector is √61 and the direction of the angle is 40 degrees option (C) magnitude of √61 and a direction angle equal to approximately 40° is correct.
Learn more about the vector here:
brainly.com/question/8607618
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