Answer:
25%
Explanation:
This question involves a single gene coding for fur color in Labrador dogs. The allele for black fur (B) is dominant over the allele for golden fur (b). This means that a heterozygous dog (Bb) will have a black fur.
According to this question, if two heterozygous parents are crossed i.e. Bb × Bb, the following gametes will be produced by each parent: B and b. Using these gametes in a punnet square (see attached image), the following proportion of offsprings will be produced:
Black fur (BB, Bb) = 3/4
Golden fur (bb) = 1/4
Hence, the percentage of offsprings that will have golden fur is 1/4 × 100 = 25%.
