Answer:
The horizontal distance the ball travels is approximately 4.055 meters
Explanation:
The given parameters are;
The height from which the child kicks the ball = 3.5 m
The horizontal speed of the ball = 4.8 m/s
Therefore, we have;
The time it takes the ball to hit the ground is given by the relation;
h = u·t + 1/2·g·t²
Where;
u = The initial vertical velocity of the ball = 0 m/s
t = The time it takes the ball to hit the ground
g = The acceleration due to gravity = 9.81 m/s²
h = The height of the ball = 3.5 m
3.5 = 0 × t + 1/2 × 9.81 × t²
3.5 = 1/2 × 9.81 × t²
∴ t² = 3.5/(1/2 × 9.81)
∴ t = √(3.5/(1/2 × 9.81) = 0.8447 s
t ≈ 0.8447 s
The time the ball takes in flight = t ≈ 0.8447 s
Therefore;
The horizontal distance the ball travels = The horizontal velocity × The time of flight
∴ The horizontal distance the ball travels = 4.8 × 0.8447 ≈ 4.055
The horizontal distance the ball travels ≈ 4.055 meters.
