Question

The point (1,0) lies on the graph of
P(x) = x^4 - 2x^3 - x+2
A. True
B. False

Answer 1

Answer:

The given statement is true.

Step-by-step explanation:

Given function is:

$P(x) = x^4 - 2x^3 - x+2$

And the given point is:

(1,0)

In an ordered pair, the first element is the input and second is the output. If we plug in the input to the function and get the respective output then the point lies on the graph of function.

For (1,0) we will put x = 1 in function and check whether we get 0 as output

$P(x) = (1)^4 - 2(1)^3 - 1+2\\= 1-2(1)-1+2\\= 1-2-1+2\\=0$

Hence,

The given statement is true.