Question

Donny, who has a mass of 75.0 kg, is riding at 25.0 m/s in his truck when he suddenly slams on the brakes to avoid hitting a squirrel crossing the road. His seatbelt brings his body to a stop in 0.500 seconds. What force does the seatbelt exert on him?

Answer 1

Answer:

F = 3750  N

Explanation:

Given that,

Mass of Donny, m = 75 kg

Initial speed, u = 25 m/s

He suddenly slams on the brakes to avoid hitting a squirrel crossing the road, final speed = 0

Time, t = 0.5 s

We need to find the force the seatbelt exert on him. The force is given by :

F = ma

a is acceleration

$F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{75\times (0-25)}{0.5}\\\\=-3750\ N$

So, the force is 3750  N.

Answer 2

The force the seatbelt exert on him is 3750 N

Using Newton's third law

f = ma

where

m = mass

a = acceleration

a = v - u / t

where

v = final velocity

u = initial velocity

t = time

Therefore,

f = m(v - u / t)

m = 75 kg

u = 25 m/s

t = 0.500 secs

v = 0 m/s (The car will stop because he applied a brake)

f = 75 × (0 - 25 / 0.5)

f = 75 × -25 / 0.5

f = 75 × -50

f = - 3750

f = 3750 N

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