Respuesta :
Answer:
500 inches
Step-by-step explanation:
Let C₁ and n₁ be the circumference and the number of rotations of the larger wheel. Also, let C₂ and n₂ be the circumference and the number of rotations of the smaller wheel. Since the distance moved by both wheels from Ally's house to her neighbor's house is the same, n₁C₁ = n₂C₂. (1)
Also it is given that half the circumference of the larger wheel is 5 inches more than the circumference of one of the smaller wheels.
So, C₁/2 = C₂ + 5
C₁ = 2(C₂ + 5) (2)
Substituting C₁ into (1), we have
n₁C₁ = n₂C₂.
n₁[2(C₂ + 5)] = n₂C₂.
Since n₁ = 10 and n₂ = 25, we have
10[2(C₂ + 5)] = 25C₂
20(C₂ + 5) = 25C₂
expanding the bracket,
20C₂ + 100 = 25C₂
collecting like terms, we have
25C₂ - 20C₂ = 100
5C₂ = 100
dividing both sides by 5, we have
C₂ = 100/5
= 20 inches
So, the distance between Ally's house and her neighbor's house is d = n₂C₂ = 25(20)
= 500 inches
The distance travelled by Ally's tricycle is [tex]500inches[/tex]
Let
[tex]d=\text{the distance between Ally's house and her neighbor's house}\\C_b=\text{the circumference of the larger wheel}\\C_s=\text{the circumference of each of the smaller wheels}[/tex]
Then, from the question
[tex]d=10C_b=25C_s\\\\\frac{C_b}{2}=C_s+5[/tex]
Eliminating [tex]C_s[/tex] from the second statement, we get
[tex]\frac{C_b}{2}=5+\frac{2C_b}{5}[/tex]
Solving for [tex]C_b[/tex],
[tex]C_b=50inches[/tex]
To calculate the distance travelled between her house and her neighbor's house,
[tex]d=10C_b\\\implies d=10\times 50inches=500 inches[/tex]
Therefore, the distance travelled between Ally's house and her neighbor's house is [tex]500inches[/tex]
Learn more about circumferences here: https://brainly.com/question/3131741