Question

An ant is climbing up a branch that is tilted 60° to the ground. It moves at a constant velocity of 0.5 cm/sec. Find the set of parametric equations that describes the path of the ant’s travel. Assume the ant starts at the origin.

Answer 1

Answer:

the set of parametric equation would be x(t) = 0.25t, y = 0.43t

Step-by-step explanation:

The computation of the set of parametric equation would be

x(t) = 0.5 cos 60 degrees t , y = 0.5 sin 60 degrees t

x(t) = 0.5 × 0.5t , y = 0.5 × 0.866 t

x(t) = 0.25t, y = 0.43t

Hence the set of parametric equation would be x(t) = 0.25t, y = 0.43t

The same is to be considered

The above equation represents the answer

Answer 2

For the entire practice:

1) B, $x(t)=0.25t$ and $y(t)=0.43t$

2) B, 4 ft.

3) A, $x=27.82$, $y=-4.9t^2+11.24t$, horizontal distance = 63.71 m