Answer:
Let
Tinky's age=x
Laa's age=x+2
According to the question
[tex]\qquad\quad {:}\longmapsto\sf 5 (x+x+2)-1=x (x+2)[/tex]
[tex]\qquad\quad {:}\longmapsto\sf 5(2x+2)-1=x^2+2x [/tex]
[tex]\qquad\quad {:}\longmapsto\sf 10x+5-1=x^2+2x [/tex]
[tex]\qquad\quad {:}\longmapsto\sf 10x+4=x^2+2x [/tex]
[tex]\qquad\quad {:}\longmapsto\sf 10x-2x+4=x^2 [/tex]
[tex]\qquad\quad {:}\longmapsto\sf x^2=8x+4 [/tex]
[tex]\qquad\quad {:}\longmapsto\sf x^2-8x-4=0 [/tex]