Respuesta :
Answer: [tex]136.2\times 10^{23}[/tex] molecules
Explanation:
According to avogadro's law, 1 mole of every substance contains avogadro's number of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=\frac{1200g}{53.06g/mol}=22.62moles[/tex]
1 mole of acrylonitrile has = [tex]6.023\times 10^{23}[/tex] molecules
Thus 22.62 moles of acrylonitrile has = [tex]\frac{6.023\times 10^{23}}{1}\times 22.62=136.2\times 10^{23}[/tex] molecules
Taking into account the definition of Avogadro's number, 1.36×10²⁵ molecules of C₃H₃N are in 1200 g.
Avogadro's Number
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
Mass molar
The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.
This case
In this case, you know the molar mass of the elements is:
- C= 12 g/mole
- N= 14 g/mole
- H= 1 g/mole
So, the molar mass of the compound C₃H₃N is calculated as:
C₃H₃N= 3× 12 g/mole + 3× 1 g/mole + 14 g/mole
Solving:
C₃H₃N= 53 g/mole
You have 1200 g of C₃H₃N. So, knowing its molar mass, you can calculate the number of moles that contain a mass of 1200 g as:
1200 g×[tex]\frac{1 mole}{53 grams} [/tex]= 22.64 moles
Then you can apply the following rule of three: If by definition of Avogadro's number 1 mole of C₃H₃N contains 6.023×10²³ molecules, 22.64 moles of C₃H₃N contains how many molecules?
amount of molecules of C₃H₃N= (22.64 moles × 6.023×10²³ molecules)÷ 1 mole
amount of molecules of C₃H₃N= 1.36×10²⁵ molecules
Finally, 1.36×10²⁵ molecules of C₃H₃N are in 1200 g.
Learn more about
- Avogadro's Number:
- brainly.com/question/11907018?referrer=searchResults
- brainly.com/question/1445383?referrer=searchResults
- brainly.com/question/1528951?referrer=searchResults
- Molar mass:
- brainly.com/question/12695086?referrer=searchResults