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A 50 Kg football player is standing still when he experiences an inelastic collision with a 150 Kg football player who is traveling at 10 m/s. What is the velocity of the player immediately after the collision?

Respuesta :

Answer:

V = 7.5 m/s

Explanation:

Given that,

Mass of player 1, m₁ = 50 kg

Mass of player 2, m₂ = 150 kg

50 kg player stands still and 150 kg player is traveling at 10 m/s

We need to find the velocity of the player immediately after the collision. As the inelastic collision occurs. The linear momentum will remain conserved. After the collision, let they move with a constant velocity say V.So,

[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\=\dfrac{150\times 10}{(50+150)}\\\\=7.5\ m/s[/tex]

So, the velocity of the player immediately after the collision is 7.5 m/s.