Answer:
V = 7.5 m/s
Explanation:
Given that,
Mass of player 1, m₁ = 50 kg
Mass of player 2, m₂ = 150 kg
50 kg player stands still and 150 kg player is traveling at 10 m/s
We need to find the velocity of the player immediately after the collision. As the inelastic collision occurs. The linear momentum will remain conserved. After the collision, let they move with a constant velocity say V.So,
[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\=\dfrac{150\times 10}{(50+150)}\\\\=7.5\ m/s[/tex]
So, the velocity of the player immediately after the collision is 7.5 m/s.