Respuesta :
Answer:
The answer is D.
Explanation:
You have to apply distance formula :
[tex]distance = speed \times time[/tex]
[tex]let \: d = 200,t = 4[/tex]
[tex]200 = s \times 4[/tex]
[tex]4s = 200[/tex]
[tex]s = 200 \div 4[/tex]
[tex]s = 50 \: m {s}^{ - 1} [/tex]
Given:-
An eagle travels 200 meters in 4 seconds
To find:-
Speed of the eagle
Solution:-
- Here
Distance=d=200m
Time=t=4s
- As we know
[tex]{\boxed{\sf Speed ={\dfrac{Distance{}_{(d)}}{Time{}_{(t)}}}}}[/tex]
- Substitute the values
[tex]\qquad\quad {:}\longmapsto\sf Speed=\dfrac {200}{4}[/tex]
[tex]\qquad\quad {:}\longmapsto\sf Speed=50m/s [/tex]
[tex]\therefore{\underline{\boxed{\bf Speed\:of\:eagle=50m/s}}}[/tex]