y-1= ±3/10(x-2)
Im not sure how to get this answer but my teacher gave it to me so i hope this helps!
The equation of the asymptote of the given hyperbola is; y - 1 = ±(3/10)(x - 2)
We are given the equation of the hyperbola as;
[(y - 1)²/9] - [(x - 2)²/100] = 1
We can rewrite this equation as;
[(y - 1)²/3²] - [(x - 2)²/10²] = 1
The general equation form of hyperbola is;
[(y - k)²/a²] - [(x - h)²/b²] = 1
Comparing this general form to our given equation we can see that;
k = 1
h = 2
a = 3
b = 10
Now the equation of the asymptote of a hyperbola follows the general formula;
y = ±[a(x - h)/b] + k
Plugging in the relevant values gives us;
y = ±(3/10)(x - 2) + 1
y - 1 = ±(3/10)(x - 2)
Read more about hyperbola asymptotes at;https://brainly.com/question/12919612
