Question

I will give brainliest to the best answer.

A random two digit number (10-99) is drawn. Find each probability

1. p(32)
2. p(odd number)
3. p(a multiple of 5)

My teacher gave an assignment on this and didn't even teach how to do it.​

Answer 1

Given that two digit numbers are used and one digit is drawn randomly.

Sample space = {10,11,...99}

n(S) = 90

32 is only one number favorable

Hence P(32) = 1/90

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Odd numbers are exactly 45.

Hence prob (odd number) = 45/90 = 1/2

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Multiples of 5 are 10,15,.....95

There are exactly 18 numbers.

Hence P(a multiple of 5) = 18/90 =1/5

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