Question

A force Ě = F, î + Fy h acts on a particle
that undergoes a displacement of g = s, it
Sy Ĵ where F, = 10 N, F, = -1 N, 8z = 4 m,
and sy=1 m.
Find the work done by the force on the
particle.
Answer in units of J.

Answer 1

Answer:

Pt 1: $W=39J$

Pt 2: θ = $19.7$

Explanation:

Part 1:

$W=FS$

$W=F_{_xs_x}+F{_ys_y}$

imagine the "i"and the "j" with the hat

$W=(10i-1j)(4i+3j)$

$W=(10*4)-(1*1)$

$W=40-1$

$W=39J$

Part 2:

$|F|=\sqrt{10^2+(-1)^2}$

$|F|=\sqrt{101}$

$|S|=\sqrt{4^2+1^2}$

$|S|=\sqrt{17}$

$W=|F||S|cos$θ

$39=(\sqrt{101})(\sqrt{17} )cos$θ

θ = $19.7$

Hope it helps