Answer:
5 + 2i
We were given the complex numbers;
a = - 2 - 5i
and
b = - i
We want to find the product;
ab^3 ^ = Exponent
We substitute the complex numbers into the expression and simplify
( - 2 - 5i ) (i)^3 ^ = Exponent
This is rewritten as:
( - 2 - 5i) (i)^2 x i ^ = Exponent
Note that
i^2 = - 1 ^ = Exponent
We substitute to obtain:
( - 2 - 5i ) x - i
Let us expand to get:
- 2 x - i + 5i x - i
This simplifies to:
2i - 5i^2 ^ = Exponent
This gives:
2i - 5 ( - 1 ) = 2i + 5
Hope This Helps
DOH! My Brian Hurts
