Answer:
It is irrational and equal to 4 multiplied by the square root of 2.
Therefore, option d is true.
Step-by-step explanation:
As the expression is
'square root of 18 plus square root of 2'.
i.e. [tex]\sqrt{18}+\sqrt{2}[/tex]
Lets solve the expression
[tex]\sqrt{18}+\sqrt{2}[/tex]
[tex]=3\sqrt{2}+\sqrt{2}[/tex] ∵ [tex]\sqrt{18}=3\sqrt{2}[/tex]
[tex]\mathrm{Add\:similar\:elements:}\:3\sqrt{2}+\sqrt{2}=4\sqrt{2}[/tex]
[tex]=4\sqrt{2}[/tex]
or
[tex]=5.65685\dots[/tex] (in decimal place)
- 5.65685 indicates that it is irrational and can not be written in the form p/q
Thus, it is irrational and equal to 4 multiplied by the square root of 2.
Therefore, option d is true.
