Question

There are 18 people on a basketball team, and the coach needs to choose 5 to put into
a game. How many different possible ways can the coach choose a team of 5 if each
person has an equal chance of being selected?

Answer 1

Answer:

He can choose by each players skill and depending on how long the game is he can sub them out throughout the game

Step-by-step explanation:

Answer 2

The total different possible ways can the coach choose a team of 5 if each person has an equal chance of being selected is, 8568 or C(18, 5)

What are permutation and combination?

A permutation can be defined as the number of ways a set can be arranged, order matters but in combination the order does not matter.

We have 18 people on a basketball team.

The coach needs to choose 5 to put into a game.

So the total different possible ways can the coach choose a team of 5 if each person has an equal chance of being selected is:

$= \rm _{18}^{}\textrm{C}_5$

$= \dfrac{18!}{5!\times 13!}$

= 8568

Thus, the total different possible ways can the coach choose a team of 5 if each person has an equal chance of being selected is, 8568 or C(18, 5)

Learn more about permutation and combination here:

https://brainly.com/question/2295036

#SPJ2