Answer:
The fewest possible number of free throws Owen attempted is 15 throws
Step-by-step explanation:
From the first half,
72% = 72/100 = 18/25, reduced to its simplest ratio.
It means that he made at least 18 free throws in the first half of the season.
From the second half,
Let x be the fewest possible outcome of free throws, and the sum of total is 60% = 60/100 = 0.6
Considering the 6 free throws during the second half of the season,
(18+6)/(25+x) = 0.6
24/(25+x) = 0.6
Solving for x,
24 = 0.6(25+x)
24 = 15+0.6x
24-15 = 0.6x
9 = 0.6x
x = 9/0.6 = 15
x = 15 free throws
The fewest possible number of free throws Owen attempted is 15 throws
