Answer:
28.8g
Explanation:
I think your chemical equation should be:
2KClO3 → 2KCl +3O2
Number of moles of KClO3
[tex] = \frac{mass}{molar \: mass} [/tex]
[tex] = \frac{69}{39 + 35.5 + 3(16)} [/tex]
[tex] = 0.6mol[/tex]
From the equation,
2 mol of KClO3 : 3 mol of 02
So...
0.6 mol of KClO3 : 0.9 mol of O2
Number of moles of O2= 0.9mol
So the mass of O2 formed = number of moles× molar mass
= 0.9 × 2(16)
= 28.8g
If 69 gram of KClO₃ decomposes then 27.036 grams of oxygen will form.
Stoichiometry helps us use the balanced chemical equation to measure the quantitative relationship and it is to calculate the amount of product and reactants that are given in a reaction.
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
The given balanced equation is
2KClO₃ → 2KCl + 3O₂
According to Stoichiometry, x gram of oxygen will form
= [tex]69\ \text{g of}\ KClO_{3} \times \frac{1\ \text{mol}\ KClO_{3}}{122.55\ g\ KClO_{3}} \times \frac{3\ \text{mol}\ O_2}{2\ \text{mol}\ KClO_{3}} \times \frac{32\ g\ O_2}{1\ \text{mol}\ O_2}[/tex]
= 27.036 grams of Oxygen
Thus from the above conclusion we can say that If 69 gram of KClO₃ decomposes then 27.036 grams of oxygen will form.
Learn more about the Stoichiometry here: brainly.com/question/14935523
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