Respuesta :

Answer:

Option (E)

Step-by-step explanation:

[tex]\frac{a}{b}=\frac{c}{d}=k[/tex]

[tex]\frac{a}{b}=k[/tex]

[tex]b=\frac{a}{k}[/tex] ------(1)

[tex]\frac{c}{d}=k[/tex]

[tex]d=\frac{c}{k}[/tex] -------(2)

Since, [tex]\frac{6a+24}{md+6b}=k[/tex]

By substituting the values of b and d from equation (1) and (2),

[tex]\frac{6a+24}{\frac{mc}{k}+\frac{6a}{k}}=k[/tex]

[tex]\frac{k(6a+24)}{6a+mc}=k[/tex]

[tex]\frac{6a+24}{6a+mc}=1[/tex]

6a + 24 = 6a + mc

mc = 24

m = [tex]\frac{24}{c}[/tex]

Therefore, Option (E) will be the correct option.