Answer:
The distance traveled by the man during the acceleration is 1186.32 meters
Explanation:
The initial velocity of the man = 40 m/s
The added acceleration rate of the man to outrun = 2.5 m/s²
The time of acceleration = 12 seconds
The relevant kinematic equation of motion is given as follows;
s = u·t + 1/2·a·t²
Where;
u = The initial velocity of the car the man is driving = 40 m/s
t = The time of travel during acceleration of the car the man is driving = 12 seconds
a = The acceleration by the man to outrun the cops = 2.5 m/s²
s = The distance traveled by the man during the acceleration
Substituting, gives;
s = 40 × 12 + 1/2 × 9.81 × 12² = 1186.32
The distance traveled by the man during the acceleration = s = 1186.32 m.
