Question

Abigail is 5 years older than Brenda.
Brenda is twice as old as Carly.

The total of their ages is less than 40.

What is Abigail’s greatest possible age?
Give your answer as a whole number of years.

Answer 1

Answer:i i think Brenda 10

Step-by-step explanation:

Answer 2

Age problems are the algebra word problem which deals with the ages of people in the present time.

Given information-

Abigail is 5 years older than Brenda.

Brenda is twice as old as Carly.

The total of their ages is less than 40.

Age problems

Age problems are the algebra word problem which deals with the ages of people in the present time.

Suppose Abigail is A, Brenda is B and Carly is C years old.

As Abigail is 5 years older than Brenda. Thus,

$A=B+5$                .... 1

As Brenda is twice as old as Carly. Thus,

$C=\dfrac{B}{2}$                    ..... 2

As the total of their ages is less than 40.

$A+B+C=40$

Keep the values of A and C from the equation 1 and 2 in the above equation,

$\begin{aligned}\\ B+5+B+\dfrac{B}{2} &=40\\ 2B+\dfrac{B}{2} &=35\\ \dfrac{4B+B}{2}&=35\\ B&=\dfrac{35}{5} \times2\\ B&=14\\ \end$

Thus the Brenda is 14 year old. As the Abigail is 5 years older than Brenda. Thus the age of the Abigail is,

$A=14+5\\ A=19$

Thus the Abigail is 19 year old.

Learn more about the age related problem here;

https://brainly.com/question/91727